(4x+1)(3x^2-14x+16)=0

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Solution for (4x+1)(3x^2-14x+16)=0 equation: 


Simplifying
(4x + 1)(3x2 + -14x + 16) = 0

Reorder the terms:
(1 + 4x)(3x2 + -14x + 16) = 0

Reorder the terms:
(1 + 4x)(16 + -14x + 3x2) = 0

Multiply (1 + 4x) * (16 + -14x + 3x2)
(1(16 + -14x + 3x2) + 4x * (16 + -14x + 3x2)) = 0
((16 * 1 + -14x * 1 + 3x2 * 1) + 4x * (16 + -14x + 3x2)) = 0
((16 + -14x + 3x2) + 4x * (16 + -14x + 3x2)) = 0
(16 + -14x + 3x2 + (16 * 4x + -14x * 4x + 3x2 * 4x)) = 0
(16 + -14x + 3x2 + (64x + -56x2 + 12x3)) = 0

Reorder the terms:
(16 + -14x + 64x + 3x2 + -56x2 + 12x3) = 0

Combine like terms: -14x + 64x = 50x
(16 + 50x + 3x2 + -56x2 + 12x3) = 0

Combine like terms: 3x2 + -56x2 = -53x2
(16 + 50x + -53x2 + 12x3) = 0

Solving
16 + 50x + -53x2 + 12x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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